## Objective

Given an array of numbers, find the minimum.

## Description

In a list of numbers, the smallest number is often referred to as the ** minimum**.

In this exercise, you have to create a function ** min()** to find and return the minimum element of a given array of numbers.

Here's the signature of the function:

```
function min(arr) {
// Your code here.
}
```

`arr`

is the array whose minimum we ought to find.

If the given array is empty, return the special number `Infinity`

; otherwise return the minimum value.

## Hints

#### Hint 1

Iterate over the given array, and at each iteration keep track of the minimum seen thus far.

#### Hint 2

In the beginning, assume `Infinity`

as the minimum.

## New file

Inside the directory you created for this course on JavaScript, create a new folder called **Exercise-8-Finding-The-Minimum** and put the .html solution files for this exercise within it.

## Solution

It's impossible to find the minimum value of an arbitrary array without iterating over all the elements therein.

Likewise, the first and foremost thing we'll do is to set up a `for`

loop iterating over `arr`

:

```
function min(arr) {
for (var i = 0; i < arr.length; i++) {
// Code to go here.
}
}
```

The next thing is to check each element inside the loop with the previously-known minimum. If it's smaller than the previously-known minimum, then obviously we need to change that value and point it to the current element.

To start with, however, we don't have any previously-known minimum. But we can use one â€” the special number `Infinity`

. Every number is less than `Infinity`

, hence it could be a good candidate for the previously-known minimum before the loop begins.

Here's the complete code:

```
function min(arr) {
var minValue = Infinity;
for (var i = 0; i < arr.length; i++) {
if (arr[i] < minValue) {
minValue = arr[i];
}
}
return minValue;
}
```

The variable ** minValue** serves to keep track of the minimum seen thus far in the array. In the end, it's returned. If the given array is empty, the loop's body doesn't execute as its condition doesn't get fulfilled, and likewise

`Infinity`

is returned, just as desired.Let's try running this on a couple of arrays:

`min([-5, 1, 0, 5, 6])`

`min([0, 0, 0])`

`min([1, 9, 10, 100])`

`min([])`

*Perfect.*